City profile · United States · North America
Seymour
City population
19,478
#2,438
in United States
#47
in Indiana
#25,895
worldwide
38.959, -85.890 · 766 km from Washington
About Seymour
Seymour is a city in Indiana, United States with a population of 19,478. It is the 2,438th largest of the 3,112 cities of 15,000 or more listed in United States, and the 25,895th largest worldwide. It lies 766 km from Washington.
Key Facts
Country
Region
Rank in region
#47of 61
Elevation
184 m
Time zone
America/Indiana/Indianapolis
Coordinates
38.959, -85.890
Record updated
2017-05-23
Entry edited, not measured
City population, GeoNames. GeoNames publishes no year for its population figures, so “record updated” is when the entry was last edited — not the date the population was measured.
Nearby Cities
All 3,112 in United StatesClosest listed cities by great-circle distance from the city centre.